16 + 24 : 64 akar pangkat 2

[tex] \sqrt{16} + \sqrt{24 } \div \sqrt{64}
= 4 + \sqrt{4 \times 6} \div 8
= 4 + 2 \sqrt{6} \div 8
= \frac{6}{8} \sqrt{6}
= \frac{3}{4} \sqrt{6} [/tex]