Matematika

Pertanyaan

Dik f(x) = 2xpangkat2+1 = g(x) x-1 tentukan fog(-1) dan gof(-1)

2 Jawaban

  • =F(g(-1)) =F(-1-1)
    =2([tex] -2^{2} [/tex] )
    =2(4)=8

    g(f(-1))=g([tex] 2x^{2} [/tex] + 1)
    =g(2([tex]-1^{2} [/tex]) +1)
    =g(2(2))
    =4-1
    =3

  • =F(g(-1)) =F(-1-1)
    =2(-2^{2}−2​2​​ )
    =2(4)=8

    g(f(-1))=g(2x^{2}2x​2​​ + 1)
    =g(2(-1^{2}−1​2​​ ) +1)
    =g(2(2))
    =4-1
    =3
    Klo salah maaf yaa

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