Matematika

Pertanyaan

limit fungsi yang no B
limit fungsi yang no B

1 Jawaban


  • [tex] {lim}{ \: x ->2 } \: \: \frac{ {x}^{2} - 4x + 4}{ {x}^{2} + x - 6 } = \frac{(x - 2)(x - 2)}{(x + 3)(x - 2)} = \frac{(x - 2)}{(x + 3)} = \frac{2 - 2}{2 + 3} = \frac{?}{?} \frac{0}{5} = 0[/tex]