luas permukaan bangun tabung betdiameter 10cm dan tinggi 10cm a.1236 cm² b.1256 cm² c.1266 cm² d.1296 cm²

Luas permukaan tabung=

(2×L. alas)+(L. selimut)

Jari-jari=½×Diameter=½×10=5 cm

L. alas=

[tex]\pi {r}^{2} = \\ 3.14 \times {5}^{2} = \\ \frac{314}{100} \times 25 = \\ \frac{314}{4} = 78.5 \: {cm}^{2} [/tex]

L. selimut=

Keliling alas×Tinggi=

[tex]2\pi \: r \times t = \\ 2 \times 3.14 \times 5 \times 10 = \\ \frac{314}{100} \times 2 \times 5 \times 10 = \\ \frac{314}{100} \times 10 \times 10 = 314 \: {cm}^{2} [/tex]

Luas permukaan=

(2×78,5)+314=

157+314=471 cm²

Terima kasih.