Matematika

Pertanyaan

tolong ya Teman :))
^_^ *_* "_"

Pakai cara ya..


tolong ya Teman :)) ^_^ *_* _ Pakai cara ya..

1 Jawaban

  • a. Panjang OQ
    [tex] {oq}^{2} = {op}^{2} - {pq}^{2} \\ {oq}^{2} = {60}^{2} - {48}^{2} \\ {oq}^{2} = 3600 - 2304 \\ oq = \sqrt{1296} \\ oq = 36[/tex]
    b. Luas OQPR
    OQPR = 2 x Luas segitiga OQP
    OQPR =
    [tex] = 2 \times \frac{1}{2} \times 48 \times 36 \\ = 1728[/tex]
    c. Panjang QR
    Luas layang2 OQPR = 2 x Luas segitiga OQP

    [tex] \frac{1}{2} \times qr \times 60 = 1728 \\ 30 \times qr = 1728 \\ qr = \frac{1728}{30} \\ qr = 57.6[/tex]