tolong di jawab dengan baik dan benar

tan 45= 1
tan 60= √3

[tex] \frac{1 + tan \: 45}{1 + tan \: 60} = \frac{1 + 1}{1 + \sqrt{3} } = \frac{2}{1 + \sqrt{3} } \\ = \frac{2}{1 + \sqrt{3} } \times \frac{1 - \sqrt{3} }{1 - \sqrt{3} } \\ = \frac{2(1 - \sqrt{3} )}{1 - 3} = \frac{2(1 - \sqrt{3} )}{- 2} \\ = - (1 - \sqrt{3} ) = \sqrt{3} - 1[/tex]