hasil dari 3akar6 dikali akar48,akar16

[tex]3 \sqrt{6} \times \sqrt{48 } \div \sqrt{16} [/tex]
[tex] \sqrt{48 \div 16} = \sqrt{3} [/tex]
[tex]3 \sqrt{6 \times 3} = 3 \sqrt{18} [/tex]
[tex]3 \sqrt{2 \times 9} [/tex]
[tex]3 \times 3 \sqrt{2} [/tex]
[tex]9 \sqrt{2} [/tex]