hasil dari 3akar6 dikali akar48,akar16

[tex]3 \sqrt{6} \times \sqrt{48} \times \sqrt{16} = 3 \sqrt{6} \times \sqrt{16 \times 3} \times 4 = 3 \sqrt{6} \times 4 \sqrt{3} \times 4 = 48 \sqrt{18} = 48 \sqrt{9 \times 2} = 144 \sqrt{2 } [/tex]