Amonium nitrat dilarutkan kedalam 1 L air murni, jika ditentukan Mr amonium nitrat 80g, Kb NH4OH 0,00002 dan pH larutan 6 masa amonimu yg dilarutkan adl

[H+] = √(10^-14/2 x 10^-5)x[NH4+]
10^-16 = 0,5 x 10^-9 x [NH4+]
[NH4+]=2 x 10^-7 
Mol NH4+ = Mol amonium nitrat = 2 x 10^-7 mol
Massa amonium nitrat = 2 x 10^-7 x 80 = 160 x 10^-7 gram = 0,16 miligram