jika f(x)=1/x dan g(x) =2x-1,maka (fog)^-1(x) =.....

(fog)= (1/(2x-1))
kalo invers, bikin aja x=
2xy-y=1
2xy=1+y
x=(1+y)/2y
y=(1+x)/2x

(fog)^-1(x) = f[g(x)] = f(2x-1) = 1/(2x-1)misal: fy = 1/(2x-1)
y(2x-1) =1
2xy-y = 1
2xy= y+ 1
x= (y+1)/(2y)
(fog)^-1 (x) = (x+1)/(2x)