persamaan grafik fungsi kuadrat yang mempunyai titik maksimum (3,2) dan malalu titik (2,0) adalah...

xp = 3 x = 2
yp = 2 y = 0

[tex]y = a {(x - xp)}^{2} + yp \\ 0 = a {(2 - 3)}^{2} + 2 \\ 0 = a {( - 1)}^{2} + 2 \\ 0 = a + 2 \\ - 2 = a \\ \\ y = a{(x - xp)}^{2} + yp \\ y = - 2 {(x - 3)}^{2} + 2 \\ y = - 2( {x}^{2} - 6x + 9) + 2 \\ y = - 2 {x}^{2} + 12x - 18 + 2 \\ y = - 2 {x}^{2} + 12x - 16[/tex]

F( x ) = a ( x ) + b
F(0) = 3 (2) + 2
F. = 6 +2=8