Berapa pH 10ml larutan (CH3CO)2 Ca 0,3M Ka=2 x 10^-5
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Pertanyaan
Berapa pH 10ml larutan (CH3CO)2 Ca 0,3M Ka=2 x 10^-5
1 Jawaban
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1. Jawaban nugroho528
Larutan garam hidrolisis bersifat basa.
[OH-] = √(Kw/Ka) x Mgaram x valensi
= √[10^-14/(2 x 10^-5)] x 0,3 x 2
=√3 x 10^-10 = (3)^0,5 x 10^-5
pOH = - log (3)^0,5 x 10^-5
= 5 - 0,5 log 3
pH = 9 + 0,5 log 3
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