diketahui f(x)=2x-3, g(x)=x+2/3-x,x#3. tentukan nilai (f 0 g) (x)

MAPEL : MATEMATIKA

KELAS : X

BAB : FUNGSI KOMPOSISI
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Diketahui :
↪f(x) = 2x - 3
↪g(x) = x + 2/3 - x
↪x ≠ 3

Ditanya
↪nilak (f o g) (x) =....?


Jawaban :
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(f o g) (x) = f(g(x)) = f(x + 2/3 - x)

(f o g) (x) = 2(x + 2/3 - x) - 3

(f o g) (x) = (2x + 4/3 - x) - 3(3 - x) /(3 - x)

(f o g) (x) = (2x + 4/3 - x) - (9 - 3x) /(3 - x)

(f o g) (x) = (2x + 3x + 4 - 9)/3 - x

(f o g) (x) = 5x - 5/3 - x



Semoga membantu....