f(x)=3x-2 g(x)= x/5x+18 , x=-18/5 tentukan (gof)^-1 (x)
Matematika
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Pertanyaan
f(x)=3x-2 g(x)= x/5x+18 , x=-18/5 tentukan (gof)^-1 (x)
1 Jawaban
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1. Jawaban NN25
[tex]gof(x) = g(f(x) \\ = g(3x - 2) \\ = \frac{3x - 2}{5(3x - 2) + 18} \\ = \frac{3x - 2}{15x - 10 + 18} \\ = \frac{3x - 2}{15x + 8} \\ [/tex]
[tex]{gof}^{ - 1}(x) = \frac{ - 8x - 2}{15x - 3} \\ go {f}^{ - 1}( \frac{18}{5} ) = \frac{ - 8( \frac{18}{5}) - 2}{15( \frac{18}{5}) - 3} \\ go {f}^{ - 1}( \frac{18}{5} ) = \frac{ \frac{ - 144}{5} - \frac{10}{5} }{54 - 3} \\ = \frac{ \frac{ - 154}{5} }{51} \\ = \frac{ - 154}{255} [/tex]