Matematika

Pertanyaan

akar 27 - 5 akar 75 + 2 akar 108 - 4 akar 48 = p akar 3

1 Jawaban

  • √27 -5√75 + 2√108 -4√48                       = p√3
    √27 - 5(√25.√3) + 2(√4.√27) - 4(√16.√3) = p√3
                 √27 - 5(5√3) + 2(2√27) - 4(4√3) = p√3
                         √27 - 25√3 + 4√27 - 16√3  = p√3
                                   3√27 - 41√3             = p√3
                            3(√9.√3) - 41√3               = p√3
                                    9√3 - 41√3              = p√3
                                                         32√3  = p√3
                                                               p  = 32√3 / √3
                                                               p  = 32

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