Turunan pertama dari f'(1) = (5x-2) / (2x+1)

[tex]\huge f(x)=\frac{5x-2}{2x+1}[/tex]
[tex]\huge \frac{d}{dx}\frac{f(x)}{g(x)}= \frac{f'g-fg'}{g^2}[/tex]

[tex]\huge \frac{d}{dx}\frac{f(x)}{g(x)}= \frac{(10x+5)-(10x-4)}{4x^2+4x+1}[/tex]
[tex]\huge \frac{d}{dx}\frac{f(1)}{g(1)}= \frac{9}{9}[/tex]
Maaf jika ada salah hitung.