koordinat fokus ellips 16x^2 + 25y^2 - 96x + 100y -156 = 0 adalah ...

[tex]16x^2+25y^2-96x+100y-156=0 \\ 16(x^2-6x)+25(y^2+4y)-156=0 \\ 16(x^2-6x+9)+25(y^2+4y+4)=156+144+100 \\ 16(x-3)^2+25(y+2)^2=400 \\ \displaystyle \frac{(x-3)^2}{25}+\frac{(y+2)^2}{16}=1 \\ a^2=25,b^2=16,c^2=b^2-a^2=9 \\ c= 3 \\ $Pusat$(3,-2) \\ $Elips horizontal$ \\ $Fokus:$ \\ (3-c,-2)(3+c,-2) \\ (3-3,-2)(3+3,-2) \\ (0,-2)$ dan $(6,2)[/tex]