tolong dong nomer 41 sama 42 :(

[tex]vmax= \sqrt{g.R.tantetha} \\ 25= \sqrt{10(60)tan tetha} \\ 625=600.tan tetha \\ 1,042=tan tetha \\ tetha=46,17 [/tex]

[tex]vmax= \sqrt{g.R( \frac{myu.tantetha}{1-myu.tantetha} )} \\ vmax=\sqrt{600( \frac{0,28+1,042}{1-(0,28)(1,042)} )} \\ vmax=\sqrt{600( \frac{1,322}{0,71} )} \\ vmax=\sqrt{600(1,86)} \\ vmax=33,4 [/tex]