Matematika

Pertanyaan

Bentuk Subtitusi :
1. X + Y =1
X + 5Y =5
2. 3X + 2Y =12
2X - Y =8
3. 2X + Y =5
3X - 2Y =4
4. 3X + 2Y =12
2X +3Y =18
Pakai Cara!

1 Jawaban

  • 1. x + y = 1 => x = 1 - y disubstitusikan ke
    x + 5y = 5
    (1 - y) + 5y = 5
    5y - y = 5 - 1
    4y = 4
    y = 1

    y = 1 disubstitusikan ke x + y = 1
    x + 1 = 1
    x = 1 - 1
    x = 0

    2. 2x - y = 8
    2x - 8 = y disubstitusikan ke 3x + 2y = 12

    3x + 2y = 12
    3x + 2(2x-8) = 12
    3x + 4x -16 = 12
    7x = 12 + 16
    x = 28 : 7
    x = 4

    x = 4 disubstitusikan ke 2x - y = 8
    2(4) - y = 8
    8 - y = 8
    8 - 8 = y
    0 = y
    y = 0

    3. 2x + y = 5
    y = 5 - 2x disubstitusikan ke
    3x - 2y = 4
    3x - 2(5 - 2x) = 4
    3x - 10 + 4x = 4
    3x + 4x = 4 + 10
    7x = 14
    x = 14 : 7
    x = 2

    x = 2 disubstitusikan ke 2x + y = 5
    2.2 + y = 5
    4 + y = 5
    y = 5 - 4
    y = 1

    4. 3x + 2y = 12
    2y = 12 - 3x
    y = 6 - 3/2x disubstitusikan ke
    2x + 3y = 18
    2x + 3(6 - 3/2x) = 18
    2x + 18 - 9/2x = 18
    2x - 9/2x = 18 - 18
    samakan penyebut
    4/2x - 9/2x = 0
    -5/2x = 0
    x = 0. -2/5
    x = 0

    x = 0 disubstitusikan ke 3x + 2y = 12
    3.0 + 2y = 12
    2y = 12
    y = 12 : 2
    y = 6

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