Tentukan nilai dari x, jika f(x)=0 1. f(x)=6x²+3 2. f(x)=x²-8x+16 3. f(x)=2x²-7x+3

1. 1. f(x)=6x²+3
0 = 6x2+ 3
6x2 + 3
6x2 = -3
x2 = -1/2
x = akar -1/2

2. f(x)=x²-8x+16
0. = x2 - 8x + 16
(x - 4 ) ( x- 4)
x = 4

3. f(x)=2x²-7x+3
0 = 2x2 -7x + 3
( 2x - 1) ( x - 3)
x = 1/2 atau x= 3